Integrand size = 18, antiderivative size = 41 \[ \int x^3 \left (c x^2\right )^{5/2} (a+b x) \, dx=\frac {1}{9} a c^2 x^8 \sqrt {c x^2}+\frac {1}{10} b c^2 x^9 \sqrt {c x^2} \]
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Time = 0.01 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {15, 45} \[ \int x^3 \left (c x^2\right )^{5/2} (a+b x) \, dx=\frac {1}{9} a c^2 x^8 \sqrt {c x^2}+\frac {1}{10} b c^2 x^9 \sqrt {c x^2} \]
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Rule 15
Rule 45
Rubi steps \begin{align*} \text {integral}& = \frac {\left (c^2 \sqrt {c x^2}\right ) \int x^8 (a+b x) \, dx}{x} \\ & = \frac {\left (c^2 \sqrt {c x^2}\right ) \int \left (a x^8+b x^9\right ) \, dx}{x} \\ & = \frac {1}{9} a c^2 x^8 \sqrt {c x^2}+\frac {1}{10} b c^2 x^9 \sqrt {c x^2} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.59 \[ \int x^3 \left (c x^2\right )^{5/2} (a+b x) \, dx=\frac {1}{90} x^4 \left (c x^2\right )^{5/2} (10 a+9 b x) \]
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Time = 0.06 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.51
method | result | size |
gosper | \(\frac {x^{4} \left (9 b x +10 a \right ) \left (c \,x^{2}\right )^{\frac {5}{2}}}{90}\) | \(21\) |
default | \(\frac {x^{4} \left (9 b x +10 a \right ) \left (c \,x^{2}\right )^{\frac {5}{2}}}{90}\) | \(21\) |
risch | \(\frac {a \,c^{2} x^{8} \sqrt {c \,x^{2}}}{9}+\frac {b \,c^{2} x^{9} \sqrt {c \,x^{2}}}{10}\) | \(34\) |
trager | \(\frac {c^{2} \left (9 b \,x^{9}+10 a \,x^{8}+9 b \,x^{8}+10 a \,x^{7}+9 b \,x^{7}+10 a \,x^{6}+9 b \,x^{6}+10 a \,x^{5}+9 b \,x^{5}+10 a \,x^{4}+9 b \,x^{4}+10 a \,x^{3}+9 b \,x^{3}+10 a \,x^{2}+9 b \,x^{2}+10 a x +9 b x +10 a +9 b \right ) \left (-1+x \right ) \sqrt {c \,x^{2}}}{90 x}\) | \(124\) |
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none
Time = 0.22 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.68 \[ \int x^3 \left (c x^2\right )^{5/2} (a+b x) \, dx=\frac {1}{90} \, {\left (9 \, b c^{2} x^{9} + 10 \, a c^{2} x^{8}\right )} \sqrt {c x^{2}} \]
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Time = 0.38 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.71 \[ \int x^3 \left (c x^2\right )^{5/2} (a+b x) \, dx=\frac {a x^{4} \left (c x^{2}\right )^{\frac {5}{2}}}{9} + \frac {b x^{5} \left (c x^{2}\right )^{\frac {5}{2}}}{10} \]
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none
Time = 0.21 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.80 \[ \int x^3 \left (c x^2\right )^{5/2} (a+b x) \, dx=\frac {\left (c x^{2}\right )^{\frac {7}{2}} b x^{3}}{10 \, c} + \frac {\left (c x^{2}\right )^{\frac {7}{2}} a x^{2}}{9 \, c} \]
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none
Time = 0.31 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.68 \[ \int x^3 \left (c x^2\right )^{5/2} (a+b x) \, dx=\frac {1}{90} \, {\left (9 \, b c^{2} x^{10} \mathrm {sgn}\left (x\right ) + 10 \, a c^{2} x^{9} \mathrm {sgn}\left (x\right )\right )} \sqrt {c} \]
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Timed out. \[ \int x^3 \left (c x^2\right )^{5/2} (a+b x) \, dx=\int x^3\,{\left (c\,x^2\right )}^{5/2}\,\left (a+b\,x\right ) \,d x \]
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